Transpose

We just learned what ket ∣x⟩\left\lvert x \right\rangle means — a N×1N\times 1 vector. Let that ALSO be called a ket. If we flip it horizontally, we get a bra ⟨x∣\left\langle x \right\rvert.

If a ket is

∣x⟩=(1+3i2+5i7)∣ψ⟩=(99000)∣ϕ⟩=(01)\begin{gather*} \left\lvert x \right\rangle=\begin{pmatrix} 1+3i \\ 2+5i \\ 7 \end{pmatrix}\quad \left\lvert \psi \right\rangle=\begin{pmatrix} 9 \\ 9 \\ 0 \\ 0 \\ 0 \end{pmatrix}\quad\left\lvert \phi \right\rangle=\begin{pmatrix} 0 \\ 1 \end{pmatrix} \end{gather*}

Then it’s counterpart is a bra

⟨x∣=(1−3i2−5i7)⟨ψ∣=(99000)⟨ϕ∣=(01)\begin{gather*} \left\langle x \right\rvert=\begin{pmatrix} 1-3i & 2-5i & 7 \end{pmatrix}\quad \left\langle \psi \right\rvert=\begin{pmatrix} 9 & 9 & 0 & 0 & 0 \end{pmatrix}\quad\left\langle \phi \right\rvert=\begin{pmatrix} 0 & 1 \end{pmatrix} \end{gather*}

You swap the columns for the rows (transpose!) and make every Element the Conjugate of itself. It becomes a 1×N1\times N matrix instead.

Let this weird transformation be known as a conjugate transpose, denoted as

⟨v∣=(∣v⟩)+\begin{gather*} \left\langle v \right\rvert=(\left\lvert v \right\rangle)^+ \end{gather*}